3.242 \(\int \sqrt{d \csc (a+b x)} (c \sec (a+b x))^{3/2} \, dx\)

Optimal. Leaf size=31 \[ \frac{2 c d \sqrt{c \sec (a+b x)}}{b \sqrt{d \csc (a+b x)}} \]

[Out]

(2*c*d*Sqrt[c*Sec[a + b*x]])/(b*Sqrt[d*Csc[a + b*x]])

________________________________________________________________________________________

Rubi [A]  time = 0.0476698, antiderivative size = 31, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.04, Rules used = {2619} \[ \frac{2 c d \sqrt{c \sec (a+b x)}}{b \sqrt{d \csc (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[d*Csc[a + b*x]]*(c*Sec[a + b*x])^(3/2),x]

[Out]

(2*c*d*Sqrt[c*Sec[a + b*x]])/(b*Sqrt[d*Csc[a + b*x]])

Rule 2619

Int[(csc[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(a*b*(a*Csc[e
 + f*x])^(m - 1)*(b*Sec[e + f*x])^(n - 1))/(f*(n - 1)), x] /; FreeQ[{a, b, e, f, m, n}, x] && EqQ[m + n - 2, 0
] && NeQ[n, 1]

Rubi steps

\begin{align*} \int \sqrt{d \csc (a+b x)} (c \sec (a+b x))^{3/2} \, dx &=\frac{2 c d \sqrt{c \sec (a+b x)}}{b \sqrt{d \csc (a+b x)}}\\ \end{align*}

Mathematica [A]  time = 0.0613883, size = 31, normalized size = 1. \[ \frac{2 c d \sqrt{c \sec (a+b x)}}{b \sqrt{d \csc (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[d*Csc[a + b*x]]*(c*Sec[a + b*x])^(3/2),x]

[Out]

(2*c*d*Sqrt[c*Sec[a + b*x]])/(b*Sqrt[d*Csc[a + b*x]])

________________________________________________________________________________________

Maple [A]  time = 0.169, size = 42, normalized size = 1.4 \begin{align*} 2\,{\frac{\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) }{b}\sqrt{{\frac{d}{\sin \left ( bx+a \right ) }}} \left ({\frac{c}{\cos \left ( bx+a \right ) }} \right ) ^{3/2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*csc(b*x+a))^(1/2)*(c*sec(b*x+a))^(3/2),x)

[Out]

2/b*cos(b*x+a)*sin(b*x+a)*(d/sin(b*x+a))^(1/2)*(c/cos(b*x+a))^(3/2)

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \csc \left (b x + a\right )} \left (c \sec \left (b x + a\right )\right )^{\frac{3}{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*csc(b*x+a))^(1/2)*(c*sec(b*x+a))^(3/2),x, algorithm="maxima")

[Out]

integrate(sqrt(d*csc(b*x + a))*(c*sec(b*x + a))^(3/2), x)

________________________________________________________________________________________

Fricas [A]  time = 1.65792, size = 84, normalized size = 2.71 \begin{align*} \frac{2 \, c \sqrt{\frac{c}{\cos \left (b x + a\right )}} \sqrt{\frac{d}{\sin \left (b x + a\right )}} \sin \left (b x + a\right )}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*csc(b*x+a))^(1/2)*(c*sec(b*x+a))^(3/2),x, algorithm="fricas")

[Out]

2*c*sqrt(c/cos(b*x + a))*sqrt(d/sin(b*x + a))*sin(b*x + a)/b

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*csc(b*x+a))**(1/2)*(c*sec(b*x+a))**(3/2),x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \csc \left (b x + a\right )} \left (c \sec \left (b x + a\right )\right )^{\frac{3}{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*csc(b*x+a))^(1/2)*(c*sec(b*x+a))^(3/2),x, algorithm="giac")

[Out]

integrate(sqrt(d*csc(b*x + a))*(c*sec(b*x + a))^(3/2), x)